The cube is composed of six square faces that meet each other at right angles( 90 degrees). It has eight vertices and 12 edges.

In a cube with sides of length a the radius of the inscribed sphere is equal to the radius of the inscribed circle for any of the square faces. From Equation 4.1) we know that
8.1) ![]()
To find the radius, R, of the circumscribing sphere, we must find the distance from the center of the cube to any vertex.
From Figure 8.1 we have that
where d is the
circumscribing radius of a square side.
From Equation 4.2) we know that
d = ![]()
So we have then

and so
8.2) R = ![]()
To find a and r in terms of R we start with Equation 8.2. This equation gives
![]()
So, solving for a we get
But we also
know that ![]()
So we have
![]()
So finally we have
8.3) ![]()
where a is the length of an edge and R is the radius of the circumscribed sphere.
To find r in terms of R consider Equation 8.1:
Substituting
the value for a in Equation 8.3 gives us
8.4) ![]()
where r is the radius if the inscribed sphere and R is the radius of the circumscribed sphere.

Triangle showing the circumscribing radius, R, from the center of the cube to a vertex of the cube.
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